![]() |
Letter Sum #2 - SolutionRating: easy Instructions:
Notes on solution, by puzzle editor: Going back to the fifth column from the right, we now have that either 1+E=10+D (if there's no carry into this column) or 2+E=10+D (if there is a carry), to get a carry into the leading column. D can't be 1, since B=1, so D must be 0, and E is 8 or 9, and A is 7 or 8. Now the second column (from the right) is 7+8 or 8+9 and must give a carry to the third column. D being 0 (and C not being 0) we have 1+E=C. Hm, so if E=A+1 and C=E+1, and A is at least 7, then A=7, E=8, C=9. Fill all this in, discover that F=5 and you're done! |
|||||||||
Copyright © 2007 Chicago Area Mensa. Chicago Area Mensa is
part of American Mensa, The High IQ
Society. The Mensa logo is a
registered trademark of Mensa International, Ltd. and American
Mensa, Ltd., all rights reserved. Mensa does not hold any opinions,
or have, or express, any political or religious views.
Lettersum_002_AuY6bG.html last updated May 15, 2003. |